Skip to content

INTERACTIVE WORKBENCH

Record count, stiffness and coupling workbench

Change the memory grammar or receiver stiffness and watch three different quantities respond: how many records exist, how much source they accommodate, and what normalized coupling follows.

Updated 6 minutes to read

Three different quantities

Count retained records first, then specify their response. The same 137 records can have different capacities and different normalized interaction strengths.

Calculate the record and its response

Choose the grammar and response inputs
A count, not the geometric contraction q used in the other workbench.
Algebraic depth. It is not the number of nested temporal roles.
Dimensionless: stiffness divided by s_ref = 4π a_ref c_ref.
Dimensionless multiplier on the depth-one terminal sector only.
Dimensionless: a/a_ref; the reference action stays fixed.
Dimensionless: c/c_ref; the reference speed stays fixed.

All inputs are illustrative model parameters. Use Tab to move between fields, type a value, then choose Update results or press Enter. Changing a field also updates after you leave it. Invalid inputs keep the last valid result.

N(10, 3) = 137 retained records. Normalized capacity C* = 137; effective stiffness σ_eff = 1. The conditional model coupling is g = 1/137 ≈ 0.007299270. This assumes the displayed response and normalization. It is not a measured value of α.

Record count N
137distinguishable records
Normalized capacity C*
137C × s_ref; dimensionless
Model coupling g
0.007299270dimensionless

Recurrence: 0 → 1 → 13 → 137.

Effective stiffness σ_eff = 1; primitive normalization σ_eff/(AV) = 1; coupling reciprocal 1/g = 137.

Each terminal sector contributes separately
Terminal depth kBranches 2ᵏ−1Continuation factor qᵈ⁻ᵏRecords nₖStiffness σₖCapacity nₖ/σₖ
111001001100
231030130
371717

Free retention, ordinary trace coupling, positive diagonal sector stiffness and a supplied continuum matching are assumptions. No laboratory constants are fitted by this calculator.

1. Count the retained records

At depth k, retain every nonempty exterior branch of a k-dimensional innovation space. Its rank is bₖ = 2ᵏ−1. Each earlier record can continue through q distinguishable modes; terminal branches stay distinct in a direct sum. This gives the exact free-grammar recurrence:

N(q,0)=0;   N(q,d)=qN(q,d−1)+(2ᵈ−1)
N(q,d)=Σₖ₌₁ᵈ qᵈ⁻ᵏ(2ᵏ−1).

The selected q=10 and d=3 give 100+30+7=137. Changing q or depth explores a different supplied grammar; it does not demonstrate that all such grammars describe physical receivers. The original ten-mode choice has a separate symmetric-receiver argument. Algebraic depth three also does not replace the six nested inner roles or their completion interface.

These are distinguishable basis records. The count alone supplies neither a probability law nor a physical duration. A nonuniform sampler can use the same record space.

2. Let stiffness change capacity

For a positive response operator K and ordinary trace source f=I_N, minimizing the quadratic energy at fixed current gives C=⟨f,K⁻¹f⟩ and E_min=j²/(2C). Uniform effective stiffness s gives C=N/s. In the diagonal sector family used here, the more general result is C=Σₖnₖ/sₖ.

The factor h changes only the oldest terminal sector. At q=10,d=3 this is the 100-record sector. Keeping the other stiffnesses fixed while setting h=2 gives normalized capacity 100/2+30+7=87. The record count remains 137. The effective scalar stiffness is then σ_eff=137/87, so C*=N/σ_eff still holds.

In a general coupled receiver, hidden directions first relax. Their Schur complement s=u−⟨b,D⁻¹b⟩ determines N/s. This workbench uses a positive diagonal family to make the dependence visible without asserting that every hidden sector is dynamically independent.

3. State the units and physical matching

The continuum convention is g=s_cont/(4πacN). Both s_cont and ac have units of energy times length. Here the sector stiffnesses are assumed already matched to that convention. This supplied finite-to-continuum identification is not derived by the calculator.

Choose fixed reference scales a_ref (action) and c_ref (speed), and set s_ref=4πa_ref c_ref. The numerical inputs are σₖ=sₖ/s_ref, A=a/a_ref and V=c/c_ref. Then:

C*=C s_ref=Σₖnₖ/σₖ;   σ_eff=N/C*
g=σ_eff/(AVN)=1/(AVC*).

Thus the displayed capacity is dimensionless C*, while dimensional capacity is C*/s_ref. A value σ_eff/(AV)=1 is a physical normalization assumption. It cannot be forced by changing units, since all quantities in that ratio are dimensionless.

At the baseline, C*=137 and g=1/137. Doubling every stiffness gives C*=68.5 and g=2/137. Doubling only the oldest sector gives C*=87 and g=1/87. Changing A or V changes the coupling while leaving both record count and this receiver capacity unchanged. These contrasts isolate the required action–speed dictionary.

What the calculator establishes

The recurrence and positive-response arithmetic are exact under the displayed assumptions. The model does not derive the stiffness, select the physical current, construct a three-dimensional continuum, or identify that current with electromagnetism. In particular, 137 alone does not predict measured α. A source theory must establish these interfaces together and test an additional observable without re-fitting the target.

Follow the derivation and its limits